Poincare inequality

The doubling condition and the Poincar e inequality are relatively standard assumptions in analysis on metric measure spaces. There are several phenomena in harmonic analysis and PDEs for which a (q;p ")-Poincar e inequality for some ">0 would be a more natural assumption than a (q;p)-Poincar e inequality. This is

We examine the validity of the Poincaré inequality for degenerate, second-order, elliptic operators H in divergence form on \({L_2(\mathbf{R}^{n}\times \mathbf{R}^{m})}\).We assume the coefficients are real symmetric and \({a_1H_\delta\geq H\geq a_2H_\delta}\) for some \({a_1,a_2>0}\) where H δ is a generalized Grušin operator,A Poincare’s inequality with non-uniformly degenerating gradient. Monatshefte für Mathematik, Vol. 194, Issue. 1, p. 151. CrossRef; Google Scholar; Li, Buyang 2022. Maximum-norm stability of the finite element method for the Neumann problem in nonconvex polygons with locally refined mesh. Mathematics of Computation, …Inequality (1.1) can be seen as a Poincaré inequality with trace term. The main result of the paper states that balls are the sets which minimize the constant in (1.1) among domains with a given volume. Theorem 1.1 The main result. Let p ∈ [1, + ∞ [.In the proof of Theorem 5.1 we need yet another result, which is a Poincaré inequality for vector fields that are tangent on the boundary of ω h (z) (see (5.1)), and with constant independent of ...The Poincar ́ e inequality is an open ended condition By Stephen Keith and Xiao Zhong* Abstract Let p > 1 and let (X, d, μ) be a complete metric measure space with μ Borel and doubling that admits a (1, p)-Poincar ́ e inequality. Then there exists ε > 0 such that (X, d, μ) admits a (1, q)-Poincar ́ e inequality for every q > p−ε, quantitatively.We show that any probability measure satisfying a Matrix Poincaré inequality with respect to some reversible Markov generator satisfies an exponential matrix concentration inequality depending on the associated matrix carré du champ operator. This extends to the matrix setting a classical phenomenon in the scalar case. Moreover, the proof gives rise to new matrix trace inequalities which ...

3. I have a question about Poincare-Wirtinger inequality for H1(D) H 1 ( D). Let D D is an open subset of Rd R d. We define H1(D) H 1 ( D) by. H1(D) = {f ∈ L2(D, m): ∂f ∂xi ∈ L2(D, m), 1 ≤ i ≤ d}, H 1 ( D) = { f ∈ L 2 ( D, m): ∂ f ∂ x i ∈ L 2 ( D, m), 1 ≤ i ≤ d }, where ∂f/∂xi ∂ f / ∂ x i is the distributional ...The weighted Poincare inequality was introduced in Blanchet et al. (2009) and Bobkov and Ledoux (2009), and using an extension of the Brascamp-Lieb inequality, is shown to hold for the class of s ...The Poincaré inequality and these Sobolev spaces are then applied to produce various results on existence, uniqueness and qualitative properties of weak solutions to boundary-value problems for degenerate elliptic, degenerate parabolic and degenerate hyperbolic partial differential equations (PDEs) of second order written in divergence form ...Given a bounded open subset Ω of R n, we establish the weak closure of the affine ball B p A (Ω) = {f ∈ W 0 1, p (Ω): E p f ≤ 1} with respect to the affine functional E p f introduced by Lutwak, Yang and Zhang in [46] as well as its compactness in L p (Ω) for any p ≥ 1.These points use strongly the celebrated Blaschke-Santaló inequality. As counterpart, we develop the basic theory ...Sep 1, 2020 · Poincaré inequality in a ball (case $1\leqslant p < \infty$) There is a weaker inequality which is derived from \ref{eq:1} ... REFINEMENTS OF THE ONE DIMENSIONAL FREE POINCARE INEQUALITY´ 3 where the inner product on the left-hand side is the one in L2( ), while on the right-hand side is the one in L2( ). This statement, by itself, is enough to get the free Poincare inequality (´ 1.4) which follows from that Mis a non-negative operator.

Sobolev's Inequality, Poincar ́ e Inequality and Compactness I. Sobolev inequality and Sobolev Embeddig Theorems Theorem 1 (Sobolev's embedding theorem). Given the bounded, open set Ω ⊂ Rn with n ≥ 3 and 1 ≤ p < n, then np W1,p n−p 0 (Ω) ⊂ L (Ω) np and W1,p n−p 0 (Ω) is continuously embedded in the space L (Ω).On the Poincare inequality´ 891 (h1) There exists R >0 such that Ω⊂B(0,R). (h2) There exists a fixed finite cone Csuch that each point x ∈ ∂Ωis the vertex of a cone C x congruent to Cand contained in Ω. (h3) There exists δ 0 >0 such that for any δ∈ (0,δ 0), Ωδis a connected set.We prove that complete Riemannian manifolds with polynomial growth and Ricci curvature bounded from below, admit uniform Poincaré inequalities. A global, uniform Poincaré inequality for horospheres in the universal cover of a closed, n -dimensional Riemannian manifold with pinched negative sectional curvature follows as a corollary. …For other inequalities named after Wirtinger, see Wirtinger's inequality. In the mathematical field of analysis, the Wirtinger inequality is an important inequality for functions of a single variable, named after Wilhelm Wirtinger.It was used by Adolf Hurwitz in 1901 to give a new proof of the isoperimetric inequality for curves in the plane. A variety of closely related results are today ...Once one has found such a "thick" family of curves, the deduction of important Sobolev and Poincaré inequalities is an abstract procedure in which the Euclidean structure no longer plays a role. See Full ... Annales de l'Institut Henri Poincare (C) Non Linear Analysis. BMO, integrability, Harnack and Caccioppoli inequalities for quasiminimizers.inequalities as (w,v)-improved fractional inequalities. Our first goal is to obtain such inequalities with weights of the form wF φ (x) = φ(dF (x)), where φ is a positive increasing function satisfying a certain growth con-dition and F is a compact set in ∂Ω. The parameter F in the notation will be omitted whenever F = ∂Ω.

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Abstract. Abstract. We give a simple and direct proof of the existence of a spectral gap under some Lyapunov type condition which is satisfied in particular by log-concave probability measures on Rn R n. The proof is based on arguments introduced in Bakry and al, but for the sake of completeness, all details are provided.We study Poincaré inequalities and long-time behavior for diffusion processes on R n under a variable curvature lower bound, in the sense of Bakry-Emery. We derive various estimates on the rate of convergence to equilibrium in L 1 optimal transport distance, as well as bounds on the constant in the Poincaré inequality in several situations of interest, including some where curvature may be ...Analogous to , higher order Poincaré inequality involving higher order derivatives also holds in \(\mathbb {H}^{N}\). In this context, a worthy reference on this inequality is [22, Lemma 2.4] where it has been shown that for k and l be non-negative integers with \(0\le l<k\) there holdsAbstract. We show that, in a complete metric measure space equipped with a doubling Borel regular measure, the Poincare inequality with upper gradients in- troduced by Heinonen and Koskela (HK98 ...

Hardy and Poincaré inequalities in fractional Orlicz-Sobolev spaces. Kaushik Bal, Kaushik Mohanta, Prosenjit Roy, Firoj Sk. We provide sufficient conditions for boundary Hardy inequality to hold in bounded Lipschitz domains, complement of a point (the so-called point Hardy inequality), domain above the graph of a Lipschitz function, the ...Poincare inequalities, pointwise estimates, and Sobolev classes Examples and necessary conditions Sobolev type inequalities by means of Riesz potentials Trudinger inequality A version of the Sobolev embedding theorem on spheres Rellich-Kondrachov Sobolev classes in John domains Poincare inequality: examples Carnot-Caratheodory spaces Graphs ...The Poincaré inequality need not hold in this case. The region where the function is near zero might be too small to force the integral of the gradient to be large enough to control the integral of the function. For an explicit counterexample, let. Ω = {(x, y) ∈ R2: 0 < x < 1, 0 < y < x2} Ω = { ( x, y) ∈ R 2: 0 < x < 1, 0 < y < x 2 }We show that Poincaré inequalities with reverse doubling weights hold in a large class of irregular domains whenever the weights satisfy certain conditions. Examples of these domains are John domains. Keywords. 46E35 reverse doubling weights Poincaré inequality John domains. TypeAbstract. We study a certain improved fractional Sobolev-Poincaré inequality on domains, which can be considered as a fractional counterpart of the classical Sobolev-Poincaré inequality. We prove the equivalence of the corresponding weak and strong type inequalities; this leads to a simple proof of a strong type inequality on John domains.This is given as exercise in a proof of a version of Poincaré's inequality for cubes which proceeds by induction on the dimension (the base case being the above one). I've managed to make a proof, but I am not sure if it is the intended one, and I get a constant 2 in the inequality (although this is probably due to a crude estimate on the step ...Poincare Inequality Meets Brezis-Van Schaftingen-Yung Formula on´ Metric Measure Spaces Feng Dai, Xiaosheng Lin, Dachun Yang*, Wen Yuan and Yangyang Zhang Abstract Let (X,ρ,µ) be a metric measure space of homogeneous type which supports a certain Poincare´ inequality. Denote by the symbol C∗ c(X) the space of all continuous func-Reverse Poincare inequality for Laplacian operator. Ask Question Asked 5 years, 11 months ago. Modified 5 years, 11 months ago. Viewed 444 timesof the constant C in the weighted inequality (1) in terms of the Poincaré constants of the superlevel sets. A similar statement holds true in the more general asymmetric case where we allow for certain weights ρ different from w on the right hand side of (1). Keywords Weighted Poincaré inequality · Poincaré constant ·Sobolev inequality ...We prove a Poincaré inequality for Orlicz-Sobolev functions with zero boundary values in bounded open subsets of a metric measure space. This result generalizes the (p, p)-Poincaré inequality for Newtonian functions with zero boundary values in metric measure spaces, as well as a Poincaré inequality for Orlicz-Sobolev functions on a Euclidean space, proved by Fuchs and Osmolovski (J ...

Thus 1/λ1 1 / λ 1 is the best constant in the Poincaré inequality since the infimum is achieved by the solution to the Dirichlet problem. Now, the crucial feature of this is that for a ball, namely Ω = B(0, r) Ω = B ( 0, r), we can explicitly compute the eigenfunctions and eigenvalues of the Laplacian by using the classical PDE technique ...

6. Poincaré inequality is given by. ∫Ωu2 ≤ C∫Ω|∇u|2dx, ∫ Ω u 2 ≤ C ∫ Ω | ∇ u | 2 d x, where Ω Ω is bounded open region in Rn R n. However this inequality is not satisfied by all the function. Take for example a constant function u = 10 u = 10 in some region. Happy to have have some discussions about it. Thanks for your help.In this paper, a simplified second-order Gaussian Poincaré inequality for normal approximation of functionals over infinitely many Rademacher random variables is derived. It is based on a new bound for the Kolmogorov distance between a general Rademacher functional and a Gaussian random variable, which is established by means of the discrete Malliavin-Stein method and is of independent ...ABSTRACT Poincare's inequality is well known: given a bounded domain G, ∥u∥p ⋚ c∥∇u∥p provided u(x) vanishes on the boundary ∂G. The case where u(x) is a vector field u(x) that does not vanish on the boundary ∂G is considered. It is shown that when either the tangential component or the normal component vanishes on the boundary ∂G, then the Poincare inequality is satisfied.As it happens, the trace Poincaré inequality is equivalent to an ordinary Poincaré inequality. We are grateful to Ramon Van Handel for this observation. The same result has recently appeared in the independent work of Garg et al. [GKS20]. Proposition 2.4 (Equivalence of Poincaré inequalities). Consider a Markov process (/B: B ≥ 0) ⊂ Ωcar´e inequality for all finite p>p 0. We prove that the lower bound p 0 is sharp. We formulate a conjecture concerning (q,p)-Poincar´e inequalities in s-John domains, 1≤q ≤p. 1. Introduction AboundeddomainGinRn,n ... ON THE (1,p)-POINCARE INEQUALITY 907 ...Using the aforementioned Poincaré-type inequality on the boundary of the evolving hypersurface, we obtain a novel Brunn--Minkowski inequality in the weighted-Riemannian setting, amounting to a certain concavity property for the weighted-volume of the evolving enclosed domain. All of these results appear to be new even in the classical non ...Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

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Poincaré inequalities for Markov chains: a meeting with Cheeger, Lyapunov and Metropolis Christophe Andrieu, Anthony Lee, Sam Power, Andi Q. Wang School of Mathematics, University of Bristol August 11, 2022 Abstract We develop a theory of weak Poincaré inequalities to characterize con-vergence rates of ergodic Markov chains.Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.Poincare--Friedrichs inequalities for piecewise H1 functions are established and can be applied to classical nonconforming finite element methods, mortar methods, and discontinuous Galerkin methods. Poincare--Friedrichs inequalities for piecewise H1 functions are established. They can be applied to classical nonconforming finite element methods, mortar methods, and discontinuous Galerkin methods.About Sobolev-Poincare inequality on compact manifolds. 3. Discrete Sobolev Poincare inequality proof in Evans book. 1. A modified version of Poincare inequality. 5.We investigate links between the so-called Stein's density approach in dimension one and some functional and concentration inequalities. We show that measures having a finite first moment and a density with connected support satisfy a weighted Poincaré inequality with the weight being the Stein kernel, that indeed exists and is unique in this case. Furthermore, we prove weighted log-Sobolev ...In Evans PDE book there is the following theorem: (Poincaré's inequality for a ball). Assume 1 ≤ p ≤ ∞. 1 ≤ p ≤ ∞. Then there exists a constant C, C, depending only on n n and p, p, such that. ∥u − (u)x,r∥Lp(B(x,r)) ≤ Cr∥Du∥Lp(B(x,r)) ‖ u − ( u) x, r ‖ L p ( B ( x, r)) ≤ C r ‖ D u ‖ L p ( B ( x, r)) The ...´ Inequalities and Sobolev Spaces Poincare 187 The Sobolev embedding theorem almost follows from the generalised Poincar´e inequality (1) when a satisfies Dr . However, the best that can be obtained in general is a weak version of the theorem.Abstract. In order to describe L2 -convergence rates slower than exponential, the weak Poincaré inequality is introduced. It is shown that the convergence rate of a Markov semigroup and the corresponding weak Poincaré inequality can be determined by each other. Conditions for the weak Poincaré inequality to hold are presented, which …Download a PDF of the paper titled Poincar\'e inequality and topological rigidity of translators and self-expanders for the mean curvature flow, by Debora Impera … ….

If μ satisfies the inequality SG(C) on Rd then (1.3) can be rewritten in a more pleasant way: for all subset A of (Rd)n with μn(A)≥1/2, ∀h≥0 μn A+ √ hB2 +hB1 ≥1 −e−hL (1.4) with a constant L depending on C and the dimension d. The archetypic example of a measure satisfying the classical Poincaré inequality is the exponential ...in a manner analogous to the classical proof. The discrete Poincare inequality would be more work (and the constant there would depend on the boundary conditions of the difference operator). But really, I would also like this to work for e.g. centered finite differences, or finite difference kernels with higher order of approximation. The main contribution is the conditional Poincaré inequality (PI), which is shown to yield filter stability. The proof is based upon a recently discovered duality which is used to transform the nonlinear filtering problem into a stochastic optimal control problem for a backward stochastic differential equation (BSDE).Poincaré Inequality Add to Mendeley Elliptic Boundary Value Problems of Second Order in Piecewise Smooth Domains Mikhail Borsuk, Vladimir Kondratiev, in North-Holland Mathematical Library, 2006 2.2 The Poincaré inequality Theorem 2.9 The Poincaré inequality for the domain in ℝ N (see e.g. (7.45) [129] ).This paper deduces exponential matrix concentration from a Poincaré inequality via a short, conceptual argument. Among other examples, this theory applies to matrix-valued functions of a uniformly log-concave random vector. The proof relies on the subadditivity of Poincaré inequalities and a chain rule inequality for the trace of the matrix$\begingroup$ @BenMcKay Admittedly that's a liberal interpretation of the question, but I took to mean 'Which manifolds admit a Poincare inequality (with $\lambda_1 > 0$)?' I admit I don't know much about this, but I think the question is not so simple in the non-compact case, for complete manifolds say.$\begingroup$ It seems to me that the Poincare inequality on bounded domains is strictly weaker than (GN)S. Could you confirm whether the exponents in the (1) Poincare-Wirtinger inequality for oscillations around the mean on bounded domains (2) Poincare inequality for functions on domains bounded in only one direction, are optimal (for smooth domains even?)?If μ satisfies the inequality SG(C) on Rd then (1.3) can be rewritten in a more pleasant way: for all subset A of (Rd)n with μn(A)≥1/2, ∀h≥0 μn A+ √ hB2 +hB1 ≥1 −e−hL (1.4) with a constant L depending on C and the dimension d. The archetypic example of a measure satisfying the classical Poincaré inequality is the exponential ... Poincare inequality, WEIGHTED POINCARE INEQUALITY AND THE POISSON EQUATION 5´ as (1.5) for each annulus. However, instead of the weighted Poincar´e inequality, we now use Poincar´e inequality by appealing to a result of Li and Schoen [15] on the estimate of the bottom spectrum of a geodesic ball in terms of the Ricci curvature lower bound and its radius., Jun 27, 2023 · For other inequalities named after Wirtinger, see Wirtinger's inequality. In the mathematical field of analysis, the Wirtinger inequality is an important inequality for functions of a single variable, named after Wilhelm Wirtinger. It was used by Adolf Hurwitz in 1901 to give a new proof of the isoperimetric inequality for curves in the plane. , 2 Answers. where fΩ =∫Ω f f Ω = ∫ Ω f is the mean of f f. This is exactly your first inequality, but I think (1) captures the meaning better. The weighted Poincaré inequality would be. where fΩ,w =∫Ω fw f Ω, w = ∫ Ω f w is the weighted mean of f f. Again, this is what you have but written in a more natural way., The Poincaré inequality (see [27,57] and the references therein) states that the variance of a square-integrable Poisson functional F can be bounded as Var F ≤ E (Dx F)2 λ(dx), (1.1) where the difference operator Dx F is defined as Dx F:= f(η + δx) − f(η). Here, η +δx is the configuration arising by adding to η a point at x ∈ X ..., We show that certain functional inequalities, e.g. Nash-type and Poincaré-type inequalities, for infinitesimal generators of C 0 semigroups are preserved under subordination in the sense of Bochner. Our result improves earlier results by Bendikov and Maheux (Trans Am Math Soc 359:3085-3097, 2007, Theorem 1.3) for fractional powers, and it also holds for non-symmetric settings. As an ..., Poincare inequality, Poincare domains, John domains, domains satisfy- ing a quasihyperbolic boundary condition. This paper was written while the author was ..., By choosing the functional F appropriately, (4) becomes a Poincaré inequality with weight ϕ, see Section 3. Such inequalities have been studied extensively because of their importance for the regularity theory of partial differential equations, see the exposition in [5]. 2. Proof Lemma 2. Let Ω be a finite measure space and p ≥ 1. Assume ..., Thus 1/λ1 1 / λ 1 is the best constant in the Poincaré inequality since the infimum is achieved by the solution to the Dirichlet problem. Now, the crucial feature of this is that for a ball, namely Ω = B(0, r) Ω = B ( 0, r), we can explicitly compute the eigenfunctions and eigenvalues of the Laplacian by using the classical PDE technique ..., inequalities as (w,v)-improved fractional inequalities. Our first goal is to obtain such inequalities with weights of the form wF φ (x) = φ(dF (x)), where φ is a positive increasing function satisfying a certain growth con-dition and F is a compact set in ∂Ω. The parameter F in the notation will be omitted whenever F = ∂Ω., Regarding this point, a parabolic Poincaré type inequality for u in the framework of Orlicz space, which is a larger class than the L p space, was derived in [12]. In this paper we obtain Sobolev–Poincaré type inequalities for u with weight w = w ( x, t) in the parabolic A p class and G ∈ L w p ( Ω × I, R n) for some p > 1, in Theorem 3 ..., poincare inequality with spectral gap 1 where 1 is the rst nonzero eigenaluev of the laplace beltrami operator with domain L= C 1(M) (in the setting with boundary take C1 0 or H 0) then we can show through fourier means or ariationalv means that Var(f) 1 1 E(f;f):, Poincar´e inequalities play a central role in the study of regularity for elliptic equa-tions. For specific degenerate elliptic equations, an important problem is to show the existence of such an inequality; however, an extensive theory has been developed by assuming their existence. See, for example, [17, 18]. In [5], the first and third, Remark 1.10. The inequality (1.6) can be viewed as an implicit form of the weak Poincar e inequality. Note that setting K= 0 (which is excluded in the theorem) leads to the Poincar e inequality. The power of this result is demonstrated in the following corollary, where the celebrated Nash inequality is obtained as a simple consequence. , Introduction. Let (E, F, μ) be a probability space and let ( E, D( E)) be a conservative Dirichlet form on L2(μ). The well-known Poincar ́ e inequality is. μ(f2) . E(f, f), . μ(f) = 0, f. …, Thus 1/λ1 1 / λ 1 is the best constant in the Poincaré inequality since the infimum is achieved by the solution to the Dirichlet problem. Now, the crucial feature of this is that for a ball, namely Ω = B(0, r) Ω = B ( 0, r), we can explicitly compute the eigenfunctions and eigenvalues of the Laplacian by using the classical PDE technique ..., 1 Answer. Poincaré inequality is true if Ω Ω is bounded in a direction or of finite measure in a direction. ∥φn∥2 L2 =∫+∞ 0 φ( t n)2 dt = n∫+∞ 0 φ(s)2ds ≥ n ‖ φ n ‖ L 2 2 = ∫ 0 + ∞ φ ( t n) 2 d t = n ∫ 0 + ∞ φ ( s) 2 d s ≥ n. ∥φ′n∥2 L2 = 1 n2 ∫+∞ 0 φ′( t n)2 dt = 1 n ∫+∞ 0 φ′(s)2ds ..., Lp for all k, and hence the Poincar e inequality must fail in R. 3 Poincar e Inequality in Rn for n 2 Even though the Poincar e inequality can not hold on W1;p(R), a variant of it can hold on the space W1;p(Rn) when n 2. To see why this might be true, let me rst explain why the above example does not serve as a counterexample on Rn., We study Poincaré inequalities and long-time behavior for diffusion processes on R n under a variable curvature lower bound, in the sense of Bakry-Emery. We derive various estimates on the rate of convergence to equilibrium in L 1 optimal transport distance, as well as bounds on the constant in the Poincaré inequality in several situations of interest, including some where curvature may be ..., In this paper we study Hardy and Poincar&#233; inequalities and their weak versions for quadratic forms satisfying the first Beurling-Deny criterion. We employ these inequalities to establish a criticality theory for such forms., The main contribution is the conditional Poincaré inequality (PI), which is shown to yield filter stability. The proof is based upon a recently discovered duality which is used to transform the nonlinear filtering problem into a stochastic optimal control problem for a backward stochastic differential equation (BSDE)., We also note that the Poincare´ and Sobolev inequalities contained in [9] show gains onthe leftofthe form1 ≤ q≤ (n/(n−1))p+δforsomeδ>0. However, ourPoincare´ inequalities have gainsonboththe leftand the right, anditisforthis reason (among those mentioned) that we do not obtain the same sharp exponents that are contained in [9]., Langevin diffusions are rapidly convergent under appropriate functional inequality assumptions. Hence, it is natural to expect that with additional smoothness conditions to handle the discretization errors, their discretizations like the Langevin Monte Carlo (LMC) converge in a similar fashion. This research program was initiated by Vempala and Wibisono (2019), who established results under ..., Lecture Five: The Cacciopolli Inequality The Cacciopolli Inequality The Cacciopolli (or Reverse Poincare) Inequality bounds similar terms to the Poincare inequalities studied last time, but the other way around. The statement is this. Theorem 1.1 Let u : B 2r → R satisfy u u ≥ 0. Then | u| ≤2 4 2 r B 2r \Br u . (1) 2 Br First prove a Lemma., mod03lec07 The Gaussian-Poincare inequality. NPTEL - Indian Institute of Science, Bengaluru. 180 08 : 52. Poincaré Conjecture - Numberphile. Numberphile. 2 30 : 29. Lecture 15 (Part 2): Proof of …, Consider a function u(x) in the standard localized Sobolev space W 1,p loc (R ) where n ≥ 2, 1 ≤ p < n. Suppose that the gradient of u(x) is globally L integrable; i.e., ∫ Rn |∇u| dx is finite. We prove a Poincaré inequality for u(x) over the entire space R. Using this inequality we prove that the function subtracting a certain constant is in the space W 1,p 0 (R ), which is the ..., lecture4.pdf. Description: This resource gives information on the dirichlet-poincare inequality and the nueman-poincare inequality. Resource Type: Lecture Notes. file_download Download File. DOWNLOAD., During the past 55 years substantial progress concerning sharp constants in Poincare-type and Steklov-type inequalities has been achieved. Original results of H. Poincare, V. A. Steklov and his … Expand, Analogous to , higher order Poincaré inequality involving higher order derivatives also holds in \(\mathbb {H}^{N}\). In this context, a worthy reference on this inequality is [22, Lemma 2.4] where it has been shown that for k and l be non-negative integers with \(0\le l<k\) there holds, Thus 1/λ1 1 / λ 1 is the best constant in the Poincaré inequality since the infimum is achieved by the solution to the Dirichlet problem. Now, the crucial feature of this is that for a ball, namely Ω = B(0, r) Ω = B ( 0, r), we can explicitly compute the eigenfunctions and eigenvalues of the Laplacian by using the classical PDE technique ..., We show that Poincaré inequalities with reverse doubling weights hold in a large class of irregular domains whenever the weights satisfy certain conditions. Examples of these domains are John domains. Keywords. 46E35 reverse doubling weights Poincaré inequality John domains. Type, Given a nondegenerate harmonic structure, we prove a Poincar\'e-type inequality for functions in the domain of the Dirichlet form on nested fractals. We then study the Hajlasz-Sobolev spaces on nested fractals. In particular, we describe how the "weak"-type gradient on nested fractals relates to the upper gradient defined in the context of general metric spaces., In mathematics, the Poincaré inequality is a result in the theory of Sobolev spaces, named after the France mathematician Henri Poincaré. The inequality allows …, In different from Sobolev's inequality, the geometry of domain is essential for Poincare inequality. Quite a number of results on weighted Poincare inequality are available e.g. in [ 9, 17, 27, 36 ]. We cite [ 8, 17, 33] for further continuation of those results. For a weighted capacity characterization of this inequalities see, [ 34 ].